Which lines are perpendicular to the line y - 1 = 1/3(x+2)? check all that apply. a. y + 2 = -3(x-4) b. y - 5 = 3(x+11) c. y = -3x - 5/3 d. y = 1/3x - 2 e. 3x + y = 7

The lines that are perpendicular to the line y - 1 = 1/3(x+2) are y + 2 = -3(x-4) and 3x + y = 7

The equation of a line in point-slope form is expressed as:

m is the slope of the line

(x0, y0) is the point on the line

Given the equation y - 1 = 1/3(x+2), compared to the general formula above, we will see that:

m = 1/3

If two lines are perpendicular, the product of their slope must be -1

Let M the slope of the line perpendicular;

mM = -1

1/3 M = -1

M = -3

Hence all the lines that are perpendicular to the line y must have a slope of -3.

The equations that falls in this categories are;

y + 2 = -3(x-4) and 3x + y = 7

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2? if not the correct answer you might need to provide more information

step-by-step explanation:

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step-by-step explanation: