Can you use the sss postulate or the sas postulate to prove qps=qrs

ΔQPS and ΔQRS are proven congurent triangles by SAS postulate only .

Step-by-step explanation:

As given the figure in the question .

In the ΔQPS and ΔQRS .

(1) QP = QR

(2) ∠PQS = ∠RQS

(3) QS = QS

Thus by using the SAS congurence property .

ΔQPS  ≅ ΔQRS

Therefore  ΔQPS and ΔQRS are proven congurent triangles by SAS postulate only .

hiking down a winding trail.

step-by-step explanation:

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1