The sum of three numbers is 148. the first number is 10 less than the second. the third number is 4 times the first. what are the numbers?

Answer
1st ⇒ 23
2nd ⇒ 33
3rd ⇒ 92

Explanation
Let the 1st term = x
The 1st term is 10 less the 2nd term. So, the 2nd term = x + 10.
The third term is 4 times the 1st term. So, 3rd term = 4×x= 4x

The sum of these 3 numbers is 148.

x + (x+10) + 4x = 148
6x + 10 = 148
6x = 138
x = 23

1st ⇒ 23
2nd ⇒ 23+10 = 33
3rd ⇒ 4×23 = 92

Ibelieve the answer is c