Mathematics, 15.07.2019 16:00 channyfilthy8735
Write an equation of a line through the point (-5, 2) perpendicular to y=13x+2.
Answers: 1
![\bf (\stackrel{x_1}{-5}~,~\stackrel{y_1}{2})\qquad \qquad \qquad slope = m\implies -\cfrac{1}{13} \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-2=-\cfrac{1}{13}[x-(-5)] \\\\\\ y-2=-\cfrac{1}{13}(x+5)\implies y-2=-\cfrac{1}{13}x-\cfrac{5}{13} \\\\\\ y=-\cfrac{1}{13}x-\cfrac{5}{13}+2\implies y=-\cfrac{1}{13}x+\cfrac{21}{13}](/tpl/images/0093/0264/6d29f.png)
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Write an equation of a line through the point (-5, 2) perpendicular to y=13x+2....
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