The reference frame in which the speed of light is 3.00 x 108m/s was called the ether. suppose in june the earth travels straight into the ether with an orbital speed of 3.0 x 104m/s . according to classical mechanics, six months later in december the measured speed on earth of light from a distant star would be

-2

7 - 9 = -2

reversed:

-2 + 9 = 7

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).