Mathematics, 15.07.2019 19:00 martinezlittleman
Prove algebraically that the square of any odd number is always 1 more that a multiple of 8.
Answers: 1
is a product of two consecutive numbers, so it's divisible by 2. Therefore, the product 
is divisible by 
. In other words, that product is a multiple of 8. So 
is always "1 more that a multiple of 8".
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Prove algebraically that the square of any odd number is always 1 more that a multiple of 8....
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