What is a zero of the quadratic function f(x)=4x^2+24+11?

The roots of this equation are x = -5.5 and x = -.5

We can find this by using the quadratic equation which is listed below.

Now in order to find the right numbers to put into this equation. we look back to the original problem. Our a value will always be the number attached to x^2 (in this case 4), the b value will be attached to x (24) and the c value will be attached to no variable (11). Now we can do the operations and solve.

-3 +/- 5/2

-3 + 5/2 = -0.5 and -3 - 5/2 = -5.5

Giving you those x values.

step-by-step explanation:

because 1/3 is a fraction. we can tell because there is a divisor symbol between the 1 and the 3. if we were to add 2 fractions together, we would add the numerators, which is the number on top, but not the denominators, which is the number on the bottom

1/3+1/3=2/3

hope this !

the formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. if a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point.