The diagonals of rectangle nopq intersect at point r. if oq=2(x+3) and pr=3x-5, solve for x.

Step-by-step explanation:

Please find the attachment.

We have been given that the diagonals of rectangle nopq intersect at point r.

We know that diagonals of rectangle are always congruent. Line segment oq is diagonal of our given rectangle.

We also know that diagonals of parallelogram bisect each other, so length of diagonal np will be two times pr.

Now, we will equate np with oq to solve for x as:

Therefore, the value of x is 4.

the formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. if a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point.