Write the equation of the line that passes through (–1, 5) and has a slope of 3 in point-slope form. a. x + 1 = 3(y – 5) b. x – 5 = 3(y + 1) c. y – 5 = 3(x + 1) d. y + 1 = 3(x – 5)

We will use the x and y values from our point (x = -1 and y = 5) along with the given slope of 3 to write the equation in point-slope form.  The point-slope form is   where x1 and y1 are the coordinates from the point.  Filling in accordingly, y - 5 = 3(x - (-1)) and y - 5 = 3(x + 1), choice C from above.

I'm not sure but i think it's 1670km/h