Eudora ran from her home to her secret laboratory at an average speed of 12 km/h she then took one of her jetpacks and flew to her school at an average speed of 76 km/h eudora traveled a total distance of 120 kilometers, and the entire trip took 2 hours. how long did eudora spend running, and how long did she spend flying using her jetpack?

She spent 0.5 hrs running to her secret laboratory and 1.5 hrs flying using her jetpacks.

Step-by-step explanation:

Eudora ran from her home to her secret laboratory at an average speed of 12 km/h. The journey with her jet pack to her school has an average speed of 76km/hr. Eudora traveled a distance of 120 kilometers.  This means the total journey when she ran and flew she could cover a distance of 120 km and the entire trip took 2 hours.

The trip can be categories into two

when she ran to her secret laboratory

Speed = 12 km/hr

let the time she ran to her  secret laboratory  = a

speed = distance /time

distance = speed × time

distance = 12 × a

distance = 12a

when she flew to her school

speed = 76 km/hr

The time she flew to her school = 2 - a

speed = distance /time

distance = speed × time

distance = 76 × 2 - a

distance = 152 - 76a

Total distance of her entire trip = 120 km

total time = 2 hrs

Total distance can be represented as

12a +  152 - 76a = 120

-64a = 120 - 152

-64a = -32

divide both side by -64

a = -32/-64

a = 0.5 hrs

she spent 0.5 hrs running to her secret laboratory

Time she flew with her jetpacks = 2 - a = 2 - 0.5 = 1.5 hrs  

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x