The function f(h)=m(1/2)^h gives the mass, m, of a radioactive substance remaining after h half-lives. iron has a half-life of 2.7 years. which equation gives the mass of a 200 mg iron sample remaining after y years, and approximately how many milligrams remain after 12 years? a) f(x) = 2.7(0.5)200; 1.7 mgb) f(x) = 200(0.5)12; 30.8 mgc )f(x) = 200(0.5)12; 30.8 mgd) f(x) = 200(0.185)12; 3.2 mg  e)f(x) = 200(0.774)12; 9.2 mg

e); 9.2 mg

Step-by-step explanation:

Given function:

where m is the mass of a radioactive substance remaining after h half-lives.

 If iron has a half-life of 2.7 years, then for iron sample of mass =200 mg ,remain after y years the equation will be

Now, to find mass remain after 12 years, substitute =12 in the equation , we get

which is equivalent to

On solving it we get,

Therefore, the correct answer is e) ; 9.2 mg

80 the answer is 80

step-by-step explanation:

16.80 times .20= 3.36

step-by-step explanation: