Mathematics, 16.07.2019 07:30 smart1212

Which of the following sequences of transformation takes points j(9,1) to j'(-3,7)? a) r0eflection across x-axis and translated (x, y) ( x-2, y-2). b) translated (x, y) ( x-2, y+2) and rotated 270 degrees counterclockwise about the origin. c) rotated 90 degrees counterclockwise about the origin and reflected across the x axis. or d) translated (x, y) (x-2, y+2) and rotated 90 degrees counterclockwise about the origin.

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Answer from: mashejaj

option D) translated (x,y) (x-2, y+2) and rotated 90 degrees counterclockwise about the origin.

Justification:

1) Translation (x,y) → (x - 2, y + 2) ⇒ (9, 1) → (9 - 2, 1 + 2) = (7, 3)

2) Rotation 90° counterclokwise ⇒ (x, y) → (-y, x) ⇒ (7, 3) → (-3, 7)

So, there you have the demonstration that the translation of J (9,1) according to (x,y) → (x - 2, y + 2), followed by a rotation of 90° counterclockwise produces the image J' (-3, 7).

Answer from: 17795

The correct option is D.

Step-by-step explanation:

It is given that sequences of transformation takes points J(9,1) to J'(-3,7).

Option A:

Reflection across x-axis

$(x,y)\rightarrow (x,-y)$

$J(9,1)\rightarrow J_1(9,-1)$

Then translated,

$(x,y)\rightarrow (x-2,y-2)$

$J_1(9,-1)\rightarrow J'(7,-3)\neq J'(-3,7)$

Therefore option A is incorrect.

Option B:

Translated,

$(x,y)\rightarrow (x-2,y+2)$

$J(9,1)\rightarrow J_1(7,3)$

Then rotated 270 degrees counterclockwise about the origin.

$(x,y)\rightarrow (y,-x)$

$J_1(7,3)\rightarrow J'(3,-7)\neq J'(-3,7)$

Therefore option B is incorrect.

Option C:

Rotated 90 degrees counterclockwise about the origin

$(x,y)\rightarrow (-y,x)$

$J(9,1)\rightarrow J_1(-1,9)$

Then reflected across the x axis.

$(x,y)\rightarrow (x,-y)$

$J_1(-1,9)\rightarrow J'(-1,-9)\neq J'(-3,7)$

Therefore option C is incorrect.

Option D:

Translated,

$(x,y)\rightarrow (x-2,y+2)$

$J(9,1)\rightarrow J_1(7,3)$

Then rotated 90 degrees counterclockwise about the origin.

$(x,y)\rightarrow (-y,x)$

$J_1(7,3)\rightarrow J'(-3,7)$

Therefore option D is correct.

Answer from: Quest

b. the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

f(-2) = -3f(1) = 6 . . . estimated from f(x) = (x+2)^2-3, which matches points on the graph (-1,-2) and (0, 1)

so the change in y-value for function f is (6 )) = 9.

the table tells us

g(-2) = 1g(1) = 31

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

Answer from: Quest

give more details

step-by-step explanation: