Solve the following system of equations by the substitution method. 10x + 10y = 1 x = y - 3 what is the value of y? -29/20 31/20 -3/2

31/20

Step-by-step explanation:

10x + 10y = 1 (1)

x = y - 3

substituting x = y - 3 in equation (1)

10(y - 3) + 10y = 1

10y - 30 + 10y = 1

20y - 30 = 1

20y = 1 + 30

20y = 31

divide 20 by bothside

20y/20 =31/20

y=31/20

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.