Line jk passes through points j(–4, –5) and k(–6, 3). if the equation of the line is written in slope-intercept form, y = mx + b, what is the value of b?

Given two points the line passes through, we can find m, the slope. The slope formula is y2 - y1 / x2 - x1.
m = 3 - (-5) / -6 - (-4)
m = 3 + 5 / -6 + 4
m = 8 / -2
m = -4
Our m value is -4. We can now take the slope-intercept form with that value, and one of the points given and fill in the variables to solve for b.
y = mx + b
-5 = -4(-4) + b
-5 = 16 + b
-21 = b

So in this case, the slope intercept form is y = -4x - 21 and b is equal to -21.

Iam not sure , but probably 750 or 7.5