The product of ab=1200. a is an integer and b is an odd integer. what is the largest possible value of b

Largest possible value of b is:

75

Step-by-step explanation:

we are given that:

ab=1200

where a is an integer and b is an odd integer.

we know that product of odd numbers is always odd.

Now, 1200= 12×100

                = 2×6×10×10

               =2×2×3×2×5×2×5

It cannot be factorized further

Now, considering the product of all odd numbers

=3×5×5

=75

Now, if we multiply any other remaining number from the factorization of 1200, we will get a even number

Hence, The largest possible value of b is:

75

75

Step-by-step explanation:

Factoring out the highest power of 2 from 1200, we find that .  Therefore, the largest possible value of is .

Hope this helped! :)

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632