Which is the graph of  f(x) = 0.5(4)x?

Find f(x) for x = 0

f(x) = 0.5(4^x)

f(0) = 0.5 * 4^0

f(0) = 0.5 * 1 = 0.5

The graph must contain point (0, 0.5).

Now find f(1).

f(x) = 0.5(4^x)

f(1) = 0.5 * 4^1

f(1) = 0.5 * 4 = 2

The graph must contain point (1, 2).

Now find f(2)

f(x) = 0.5(4^x)

f(2) = 0.5 * 4^2

f(2) = 0.5 * 16 = 8

The graph must contain point (2, 8).

Now find f(3)

f(x) = 0.5(4^x)

f(3) = 0.5 * 4^3

f(3) = 0.5 * 64 = 32

The graph must contain point (3, 32).

Find a graph that has the points (0, 0.5), (1, 2), (2, 8), and (3, 32).

The only graph that contains those 4 points is choice A.

The distance from point a to point c across the coordinate plane is aproxamatly 8.94 rounded to the nearest hundredth. you use a^2 + b^2 =c^2