Me its a huge emergency which of the following statements have the same result? explain each step in solving each one. i. f(2) when f(x) = 3x + 2 ii. f-1(3) when f(x) = 2 x minus 7, all over 3 iii. 2y + 14 = 4y − 2

I.
First, plug in the number two in the place of x.
f(2) = 3(2) + 2.
Simplify
f(2) = 6+2
f(2) = 8

II.
First, we need to find the inverse function of x.
To do this, we begin by replacing f(x) with y, and switching the x and y values.
y= (2x-7)/3
x= (2y-7)/3
Then we solve for y.
3x = 2y-7
3x + 7 = 2y
(3x+7)/2 = y
Replace y with f^-1(x)
f^-1(x)= (3x+7)/2
Now that we have the inverse function, plug in 3 for x.
f^-1(x) = (3(3) + 7)/2
f^-1(x) = (9+7)/2
f^-1(x) = 16/2 = 8.

III. 2y+14 = 4y-2
Solve for y
14 = 2y - 2
16 = 2y
y = 8

So, since all of the statements have the result of 8, then all the statements have  the same result.

Hope this helps!

I’m not sure i’m sorry

Idon’t know what the answer is i wish i could