Check my only two questions that i have answered, but want to make sure i am correct what values for (0 ≤ theta ≤ 2pi ) satisfy the equation? images below for the two problems

Problem 9 is correct. Nice work.



Problem 10 however, is incorrect.

Keep in mind that,
tan(x) = sin(x)/cos(x)
If we tried to plug in x = pi/2, then we'd get an error.
Why? Because cos(x) is equal to 0 when x = pi/2
The denominator becomes 0 and we can't divide by zero.

Tan(x) is undefined when x = pi/2
So overall, x = pi/2 is not part of the domain of tan(x). 
Consequently, x = pi/2 is not part of the domain of f(x) = cos(x)-tan(x)*cos(x)
This allows us to rule out choice C and choice D

The answer comes down to either A or B. Let's try choice A.
Plug in x = 0 and see what happens.
f(x) = cos(x)-tan(x)*cos(x)
f(0) = cos(0)-tan(0)*cos(0)
f(0) = 1 - 0*1
f(0) = 1
We don't get a result of 0 like we want, so x = 0 is not a root of f(x)
We can cross choice A off the list.

Let's see what happens if we try out the x values for choice B
Plug in x = pi/4
f(x) = cos(x)-tan(x)*cos(x)
f(pi/4) = cos(pi/4)-tan(pi/4)*cos(pi/4)
f(pi/4) = sqrt(2)/2-1*sqrt(2)/2
f(pi/4) = 0
Now plug in x = 5pi/4
f(x) = cos(x)-tan(x)*cos(x)
f(5pi/4) = cos(5pi/4)-tan(5pi/4)*cos(5pi/4)
f(5pi/4) = -sqrt(2)/2-1*(-sqrt(2)/2)
f(5pi/4) = 0
Both inputs x = pi/4 and x = 5pi/4 lead to f(x) = 0
So these inputs are roots of f(x) on the interval [0,2pi]

The answer for problem 10 is choice B

A graphing calculator can help you check your work. I find it useful to rewrite the equations so you are looking for the zeros. (That's generally how you'd solve them anyway.)

9. correct
10. {π/4, 5π/4} is a better choice (The tangent is undefined where cos(θ)=0, so those angles are not in the solution set.)

Multiply 9 and 67. then multiply 3 with 67. lastly the answer that you got for 9x67 is to be subtracted by the answer you got for 3x67