What is the equation of the line that is parallel to the line y − 1 = 4(x + 3) and passes through the point (4, 32)? y = –x + 33 y = –x + 36 y = 4x − 16 y = 4x + 16

The given line is in point-slope form. Replace the point values with the new point and you will have your parallel line. Solve for y by adding the opposite of the constant on the left.

y - 32 = 4(x - 4) . . . . point (-3, 1) replaced with point (4, 32)

y = 4x + 16 . . . . . . . add 32 to both sides of the equation and simplify

300b(x) is graphed by the functio

1. isolate the variable, in this case, d. subtract 35.5 on both sides of the equation.2. 52 subtracted by 35.5 is 16.53. therefore your answer would be d= 16.5this is the basics of pre algebra, isolating variable through adding, subtracting, multiplying, and dividing, if you have any other questions to ask just comment!