The solution to this system of equations lies between the x-values -2 and -1.5. at which x-value are the two equations approximately equal? y=1/(x+2) y=x^2+2 a) -1.5 b) -1.6 c) -1.7 d) -1.8

x = -1.8  two equations approximately equal.

Step-by-step explanation:

Given : y = ,y =

To find : which x-value are the two equations approximately equal.

Solution  : We have given that

y = -----( equation 1)

------( equation 2).

Plug the of equation 2 in 1

=  .

= 1.

x³+2x² +2x+4 = 1

On subtracting 1 both sides.

x³+2x² +2x+3 = 0

For x = -1.8

Therefore,  x = -1.8  two equations approximately equal.

1e+27

step-by-step explanation:

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1