Two cars leave a town at the same time heading in opposite directions. one car is traveling 12 mph faster than the other. after 2 hours, they are 232 miles apart. what is the speed of each car? 52 mph; 64 mph 55 mph; 70 mph 92 mph; 104 mph 98 mph; 110 mph?

D = rt.  The first car's rate is r, and the other one, going faster, is r + 12.  The time they travel is 2 hours.  Since one is going faster than the other, he has gotten farther.  But, regardless of that, the distance between them is 232.  So the distance the first one travels, r*t, which 2r, plus the distance the second one travels, 2(r+12) = 232.  2r + 2r + 24 = 232.  Solve for r.  4r = 208 and r = 52.  The slower one goes 52 and the faster one goes 64

The first cars speed is X miles per hour.
 The 2nd cars speed is X + 12 miles per hour

X + X +12 = 232 / 2

2x +12 = 116

2x = 116-12

2x = 104

x = 104 / 2
x = 52

x+12 = 52+12 = 64

 The 2 cars are driving 52 and 64 miles per hour

In the first triangle 80+20+p=180 (since sum of all angles of a triangle is 180)so p= 80also in second triangle 55+45+q=180 (since sum of all angles of a triangle is 180)so q=80so we can conclude that p=80 degrees q=80 degrees so p=q=80 degreeshence option b is correct