Agift box is 15 inches long, 10 inches wide, and 3 inches high. how much wrapping paper is needed to wrap the gift box?
a. 225 in. 2
b. 450 in. 2
c. 525 in. 2
d. 650 in. 2

So surface area
there are 6 faces
front face=height times legnth
back fase=front face=height times legnth
side1=side2=height times width
top=bottom=legnth times width

surface area=front face+back face+side1+side2+top+bottom=hl+hl+hw+hw+lw+lw = 2hl+2hw+2lw=2(hl+wh+lw)

l=15
h=3
w=10
subsitute
SA=2((3 times 15)+(3 times 10)+(10 times 15))
SA=2(45+30+150)
SA=2(225)
SA=450

answer is B 450 in^2

200 miles.45 x 3 (charge per day times days)135$205$ - 135$ = 70$0.35x = 70divide both sides by 0.35200