Fill in the missing information. clyde clement wants to analyze a shipment of bags of cement. he knows the weight of the bags is normally distributed so he can use the standard normal distribution. he measures the weight of 600 randomly selected bags in the shipment. next, he calculates the mean and standard deviation of their weights. the mean is 50 lbs. and the standard deviation is 1.5 lbs. clyde uses the normal distribution table to calculate the number of bags in each segment of the distribution.

Standard deviation         Percentage from table    Number of bags out of 600

-2 to -1 (47 to 48.5 lbs)    13.6%                                   82

-1 to 0 (48.5  to 50 lbs)     34.1%                                  205

0 to +1 (50  to 51.5 lbs)     34.1%                                  205

+1 to +2 (51.5  to 53 lbs)     13.6%                                  82

Step-by-step explanation

standard deviation is 1.5 lbs and mean is 50 lb, then:

mean - 2*standard deviation  = 47 lb

mean - 0*standard deviation  = 50 lb

mean + 2*standard deviation  = 53 lb

0.341*600 = 205

0.136*600 = 82

The percentages are shown in the figure attached.

the answer is d

the answer is in the first quadrant, which make the y-int positive.

since the dots are going down, therefore the correlation is negative

i hope it is right.

what