If the area of a rectangle is 16s^2t and the length is 8st^2, what would be the width of the rectangle, given that width is found by dividing area by length? simplify the answer. a)2stb)2/st(not correct)c)2s/td)t/2s

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

828. all there is to it!

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thats the rounding one, but if you just click the top left, it shows you all the calculators you may need!