The equation h(t)=−16t2+19t+110 gives the height of a rock, in feet, t seconds after it is thrown from a cliff. what is the initial velocity when the rock is thrown? enter your answer in the box. = ft/s

For this case we have an equation of the form:
 
 Where,
 a: acceleration
 vo: initial speed
 h0: initial height.
 In this case we have the following equation:
 
 Therefore, the initial velocity is:
 
 
 The initial velocity when the rock is thrown is:
 vo = 19 ft / s

We know that


 Where: 
 a: is the acceleration
 vo: is the initial velocity
 h0: is the initial height

in this problem
a=-32 ft/sec²
v0= 19 ft/sec
h0=110 ft
 Substituting values we have:

  The initial velocity is : vo = 19 feet / s

 The answer is
 The initial velocity is  vo = 19 feet / s