Answers: Â
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Question  # 1) from first graph:
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The answer is: Â "Â 3Â " .Â
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Â
  → Â
 ; in  "simplest form" , is:  " 3 " .Â
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Question #2)Â Â from second graph:
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The answer is: Â "Â 4Â " .
_____________________________________________________          →  " (the slope of BE) over (the slope of AE) " ;Â
     that is:  " (the slope of BE) / (the slope of AE) " ;
in  "simplest form" ,  is:  " 4 " .Â
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Explanation:
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For Question #1)Â
AD = 9 units (counted from the "attached graph").Â
AB = 3 units (counted from the "attached graph").
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We are asked to write: Â "AD over AB" ; in "simplest form" ;Â
   →  AD/AB  = " 9/3 " =  " (9÷3) / (3÷3) " = "(3/1)"  =  " 3 ÷ 1 " =  3 .
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   →  The answer is:  " 3 " .
_____________________________________________________            →  "AD over AB" ; in "simplest form" ;  is:  " 3 " .Â
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   →  AD/AB =  " 3 " .
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Question 2): Â From second graph:
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Find the: Â " (slope of BE) / (slope of AE) " ; Â in "simplest form" :
From examination of the "second graph attached" :
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The "slope of BE" = rise/ run = 5/1 .
The "slope of AE" = rise/ run = 5/4 .
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So: Â "(the slope of BE) / (the slope of AE) Â ;
                      = (5/1) / (5/4) ;Â
                      Â
                      =Â
÷Â
;
 → To divide a fraction, you multiply the "reciprocal of the fraction; as follows:
                      =Â
*
;
            →  Both " 5 's " cancel out to " 1 "; since: "{5 ÷ 5 = 1 }" ; Â
            →  And we can rewrite as:
                      =Â
*
;
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                      =   1  *  4 ;
                      =  " 4 " .
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            →  The answer is:  " 4 " .
___________________________________________________________              →  "AD over AE" ; in "simplest form" ;  is:  " 4 " .Â
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