What is the standard form of the equation of a circle that has its center at (-2,-3) and passes through the point (-2,0)?

Step-by-step explanation:

The standard form of the equation of a circle that has its center(h,k) and passes through the point (x,y) is given by :-

, where r is the radius of the circle.....(1)

When (h,k)=(-2,-3) and (x,y)=(-2,0), the above equation will become :

When we put and center =(h,k)=(-2,-3)  in (1), we get

Hence, the standard form of the equation of a circle that has its center at (-2,-3) and passes through the point (-2,0) is given by :-

step-by-step explanation:

the ratio of red paint to blue paint is always 9/7. that means that, whatever x's value, (4x+12)/(4x-4) has that same ratio. so, set up an equation and cross-multiply to solve for x:

9/7 = (4x+12)/(4x-4)

9(4x-4) = 7(4x+12)

36x - 36 = 28x + 84

8x - 36 = 84

8x = 120

x = 15