The front of a garage is a square 15 ft on each side with a triangular roof above the square. the height of the triangular roof is 10.6 ft. to the nearest hundred, how much force is exerted by an 80 mi/h wind blowing directly against the front of the garage? use the formula f = 0.004av2.

See the picture in the attached figure to better understand the problem

we know that
Area of the square=b*h----->15²----> 225 ft²

Area of the triangular roof=b*h/2-----> 15*10.6/2----< 79.5 ft²

The total area of the front of the garage is= 225 + 79.5----> 304.5 ft²

Find the force of the wind against the front of the garage
Use the formula for force
F = 0.004*A*v²

Substitute 304.5 for A and 80 for v
so
F ≠ 0.004*(304.5)*(80)²------> F=7795.2------> F=7800 lb

the answer is
An 80 mi/h wind exerts a force of about 7800 lb against the front of the garage