The vertices of a triangle are p(−3, −4), q(3, 4), and r(−6, −3). name the vertices of rx = 0 (pqr). a. p'(3, −4), q'(−3, 4), r'(6, −3) b. p'(−3, −4), q'(3, 4), r'(−6, −3) c. p'(−3, 4), q'(3, −4), r'(−6, 3) d. p'(3, 4), q'(−3, −4), r'(6, 3)

The correct answer is A) P'(3, −4), Q'(−3, 4), R'(6, −3)

Rx = 0 indicates a reflection over the y-axis. 

The rule for such a transformation is:
(x, y) --> (-x, y)
which means that the x-coordinate changes sign and the y-coordinate stays the same.

Therefore:
P(-3, -4) --> P'(3, -4)
Q(3, 4) --> Q'(-3, 4)
R(-6, -3) --> R'(6, -3)

These points are those in option A).

Ithink the right answer could be 50%