Simplify this radical. which ordered pair makes both inequalities true? y > –3x + 3 y > 2x – 2 (1,0) (–1,1) (2,2) (0,3)

First, split this inequality then try each answer. 

y>-3x+3y>2x-2
split this into two and simplify each,
y > -3x + 3y                                  -3x+3y > 2x - 2
y - 3y > -3x                                    3y>2x+3x - 2
-2y > -3x                                          3y>5x -2
2y<3x                                          

Substituting all the 3 ordered pairs, none of them makes the inequalities true.