The given figure is a net for a triangular prism. the lengths in the shape are: a = 12 inches, b = 40 inches, c = 30 inches, d = 37 inches, and e = 13 inches. what is the total surface area of this figure?

I know it is late but for future reference by others who area asking

Total surface area is 3,180 square inches

Step-by-step explanation:

step 1--find the area of the triangle 1

A= 1/2 ab

= 1/2(12 in)(40 in)

=1/2 (480 sq. in)

= 240 sq. in

so in similarly of triangle 2 will be the same as triangle 1 = 240 sq. in.

step 3-find the area of rectangle 3

A= cd

=(30 in)(37 in)

= 1,110 sq. in

step 4-find the area of rectangle 4

A=bc

=(40 in)(30 in)

=1,200 sq in.

step 5-find the area of rectangle 5

A= ce

=(30 in)(13 in)

=390 sq in.

Add all the areas together to get total surface area of the given figure

Total surface area = 2(1/2ab) + (cd) + (bc) + (ce)

=2(240) sq in. + 1,100 sq in. + 1, 200 sq in. + 390 sq in.

= 480 sq in + 1,100 sq in. + 1, 200 sq in. + 390 sq in.

=3,180 sq in.

the answer is somewhere there guys it really . there im just not gonna answer

step-by-step explanation:

but i'm guessing ur first option tho

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.