Which series of transformations results in the image being congruent to the pre-image? (x, y) → (x, –y) (x, y) → (x + 5, y) (x, y) → (–x, y) (x, y) → (x + 1, y) (x, y) → (–x, –y) (x, y) → (2x, y) (x, y) → (0.5x, 0.5y) (x, y) → (x, –y) (x, y) → (x, y + 8) (x, y) → (x – 4, y) (x, y) → (x, y + 3) (x, y) → (3x, 3y)

"images of transformation are congurent if they were translates, mirrored/flipped or rotated

1) (x, y) → (x, –y) flipped

(x, y) → (x + 5, y) translated

(x, y) → (–x, y) flipped

->is congruent

2) (x, y) → (x + 1, y) translated

(x, y) → (–x, –y) flipped

(x, y) → (2x, y) scaled->not congruent

3) (x, y) → (0.5x, 0.5y) scaled-> not congurent

(x, y) → (x, –y)

(x, y) → (x, y + 8)

4) (x, y) → (x – 4, y) translated

(x, y) → (x, y + 3) translated

(x, y) → (3x, 3y) scaled->not congruent

so only the first series of transformations has congruent after image"

Step-by-step explanation:

4 candies

step-by-step explanation:

7 x 28 = 196

200 - 196 = 4 candies remaining.

hope this is what you were asking for!

step-by-step explanation: