Asap! 1. in δabc, m∠a = 90° and an is an altitude. if ab = 20 in and ac = 15 in, find bc, bn, nc, an. 2. in the δabc, ab = 16 in, bc = 9 in, ac = 10 in. ad ⊥ to the extended bc. find cd.

2= 4 1/6

Step-by-step explanation:

draw the diagram and extend BC to D

draw AD

use the Pythagorean Theorem with triangle ADC

call AD "h"

call DC "x"

h2+x2=102

now use the Pythagorean Theorem with triangle ADB

AD=h, AB=16, DB=(x+9)

h^2+(x+9)^2=16^2

from the first equation get h^2=10^2-x^2

from the second equation get h^2=16^2-(x+9)^2

set the two right sides equal to each other because they both equal h2

10^2-x^2=16^2-(x+9)^2

100-x^2=256-x^2-18x-81

cancel -x2 from both sides

100=256-18x-81

100=175-18x

100-175=-18x

-75=-18x

18x=75

x=75/18

x=4.1666... inches or 4 1/6 inches for the length of DC

a) 0

step-by-step explanation:

i^413 x i^0 = 0 as any number multiplied by a zero is

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