Aregular hexagon has a radius of 20 in. what is the approximate area of the hexagon

Remark

You need 2 facts to solve this 

1.   The area of a hexagon is 

     A = 3*(sqrt(3) ) * a^2/2 

     Just to make this clear, I'll put it in Latex

2. The second fact you need to know is that the radius = the length of the side a.

Givens

r = 20 in

a = r where a is the length of the side of a hexagon.

Formula Substitute and solve.

A = 3*(sqrt(3) * a^2 ) / 2

A = 3*(sqrt(3) * 20^2) / 2

A = 3*sqrt(3) * 400 / 2

A = 3*sqrt(3) * 200

A = 3*1.7321 * 200

A = 1039 square inches.

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

you probably already have the answer but anyways it's b. 15.0

step-by-step explanation: