Park rangers released 12 fish into a pond in year 0. each year, there were twice as many fish as the year before. how many fish were there after x years? write a function to represent this scenario.

The function would be,

Step-by-step explanation:

Given,

Park rangers released 12 fish into a pond in year 0,

Thus, the initial number of fish = 12,

Also, there were twice as many fish as the year before,

⇒ After 1 year the number of fishes = 2(12) = 12(2),

Similarly,

After 2 years = 2(12(2))= 12(2)²,

After 3 years = 2(12(2)²) = 12(2)³,

................, so on,....

Thus, the number of fishes after x years would be,

Let f(x) represents the number of fish after x years,

Which is the required function that the given scenario.

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.

answer: howdy

step-by-step explanation: