Hello can you me posted picture of question

Hello!

First you have to find the probability of them happening separately

To find this you do the amount of favorable outcomes over the total amount of outcomes

Joey is only 1 kid and there are 12 total

This is a chance of 1/12

Chloe is 1 kid out of 11 now since Joey was already picked

This is a chance of 1/11

Zoe is 1 kid out of 10 since Joey and Chloe was already picked

This is a chance of 1/10

To find the probability of them happening separately you multiply them together

1/12 * 1/11 * 1/10 = 1/1320

The answer is C) 1/1320

Hope this helps!

Maybe the answer is 20mm. all i really did was just multiply, which is obvious.