22.    what  is  an  equation  of  the  parabola  with  vertex  at  the  origin  and  focus  (−4,  0)? a.) x = 1/16y^2 b.) x = -1/16y^2 c.) y = -1/16x^2 d.) y = 1/16x^2

The correct answer for the question shown above is the second option (Option b), and the option cwhich is:

 b) x = -1/16y^2
 c) y=-1/16x^2

 The explanation is shown below:

 The focus of a parabola is (h,k+1/4a), then, you have:

 h,k= (0,0)
 1/4a=1/4(-1/16)

 Then, you obtain:

 1/4a=-4

 Therefore, the focus of the equation of the parabola x = -1/16y^2 and the parabola y=-1/16x^2 is F(0-4)

 So, as you can see, the correct answer is the options mentioned before, the option b and the option c.
 

Letter b sorry i’m i’m wrong xx