How many real solutions does y = (-x + 4)^2 have?

Short answer 1

Comment
There are a couple of ways of doing this to show there there is just one solution. The most easily done way is to graph the quadratic. I have done that for you. 

Notice that the quadratic touches the x axis, it does not cut it in two places or no places. When a quadratic just touches the x axis, it has only one solution.

Method 2
The quadratic is shown in the vertex form. If there was a number outside he bracket showing squares then you would get

y = (-x + 4)^2 + 4 (drawn in blue)
y = (-x + 4)^2 -  6 (drawn in green) 

These two examples show what the vertex form would look like if the axis was cut in 2 places or no places and there would be no solution for the first one and 2 places for the second one.

Ithink it is 7. 16

Abit confused about what you mean, but i think you might be referring to slope intercept form: y = mx + bin that case b, or the y intercept is already given.(0,-1)find the slope by using the formulay2 - y1/x2 - x1the final slope will be 4/2, equivalent to 2.now your equation should look like thisy = 4/2x -1sorry if this didn’t you out!