Find the coefficient of the x^3y^3 term in the expansion of (3x-y)^6

Step-by-step explanation:

From binomial theorem, we can know

first term would be x^6

2nd term x^5

3rd term x^4

4th term x^3

Also, from binomial theorem, we can know

first term would be y^0

2nd term would be y^1

3rd term would be y^2

4th term would be y^3

We can see that we are looking for the 4th term (x^3y^3).

To find coefficient of 4th term, we use write:

We can expand 6C3 using formula:  

Now, we have:

Thus, the coefficient is -540

i dont know

step-by-step explanation:

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)