I'm on a timer! a 4lb force acting in the direction of (4,-2) moves an object just over 7 ft from the point (0,4) to (5,-1). find the work done to move the object to the nearest foot-pound i don't know if the answer ii chose is correct. can someone check?

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

$75.00

step-by-step explanation:

i = prt

i = 1,5000 * 0.025 * 2

i = 75

i dont know the answer but here's a picture of a dog