Use the x-intercept method to find all real solutions of the equation. x^3-9x^2+20x-12=0

For this case we have the following function:
 x ^ 3-9x ^ 2 + 20x-12 = 0
 Rewriting we have:
 (x-6) * (x-2) * (x-1) = 0
 Therefore, the solutions are given by:
 Solution 1:
 x-6 = 0
 x = 6
 Solution 2:
 x-2 = 0
 x = 2
 Solution 3:
 x-1 = 0
 x = 1
 
 x = 6
 x = 2
 x = 1

Its d so thats how it would would back from 1.0 form three four two