The displacement, d, in millimeters of a tuning fork as a function of time, t, in seconds can be modeled with the equation d = 0.6 sin (3520rt) . what is the frequency of the tuning fork? a,1/3520 hz b. 1/1760 hz c. 1760 hz d. 3520 hz

C is correct. 1760 Hz

Step-by-step explanation:

The displacement (d) in millimeters of a tuning fork as a function of time t

If we compare with wave equation

If we compare it with our equation we get

As we know the formula of

Thus, The frequency of the tuning fork is 1760 Hz

the inequality is:

250c+180g≥950

step-by-step explanation:

let c denotes the number of days in a week   miyoko worked as a cryptographer.

and g denotes the number of days in a week she works as a geologist.

now we are given that she earns $250 for every day she works as a cryptographer,and earns $180 for every day she works as a geologist.

now miyoko's goal is to earn more than $950 this week.

hence, the inequality could be represented as:

250c+180g≥950

step-by-step explanation:

because 1/3 is a fraction. we can tell because there is a divisor symbol between the 1 and the 3. if we were to add 2 fractions together, we would add the numerators, which is the number on top, but not the denominators, which is the number on the bottom

1/3+1/3=2/3

hope this !