In this punnett square, what is the ratio of homozygous to heterozygous offspring? in the punnett square, what percentage of the offspring are homozygous recessive?

1. The Ratio of homozygous to heterozygous: 1:1 2. Percentage of homozygous recessive: 50%

Explanation:

In Punnett square box we put alleles of one parent in top horizontally- T is given here and another parent in vertically- t is given.

Alleles of parents cross to produce offspring. First of all we need to find what are the rest of the alleles of parents, in bottom right offspring is tt that means the second allele of the horizontal parent must be t too.

And now as Tt offspring is given on the top left so the other allele for vertical parent must be t.

As now we get all alleles for parents now the cross between t from horizontal and t from vertical parent cross n produce tt.

So,  we have four offspring- Tt, tt, Tt, and tt where tt is homozygous recessive and Tt is heterozygous.

The Ratio between homozygous and heterozygous is 2/2= 1/1 or 1:1, the percentage of homozygous recessive is 2/4×100 = 50%

y=mx+

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6