Best answer gets brainliest: the line that is the perpendicular bisector of the segment whose endpoints are r(-1, 6) and s(5, 5) i have to write the equation of the line in standard form but i can't find out what kind of equation to write for this. whoever can me with this will get brainliest.

Hello,
1) We must find the equation of the line RS:
R=(-1;6)S=(5;5)
y-6=(x+1)(5-6)/(5+1)y=-1/6*(x+1)+6
 y=-x/6+35/6 Slope=-1/6
The perpendicular has the slope 6.

2) Find M the middle of [RS]M=((5-1)/2;(6+5)/2)=(2:11/2)
3) Equation of the perpendicular bisector:
y-11/2=(x-2)*6y=6x-12+11/2
So y=6x-13/2
And sorry for my poor english

3)

Ithink it would be 160 people