Given the function, f(x)=()+(64x)-192 find the zeros

There are a few ways to find the zeros. I am going to use the grouping method.

NOTE: GCF = Greatest Common Factor

The function:  

Lets group and

Factor
Find GCF
GCF =

Divide out the GCF


Factor From:


Now factor 64x -192
GCF of 64 and 192 = 64
Factor out 64 from 64x - 192


Factor Form:


Now that we have factored the groups, bring them together.





Since (x-3) is the GCF of , factor (x-3) out.


Factor Form:


Now set to zero and solve for x.



Take the square root of both sides of the equal sign:




Now for (x-3)
x - 3 = 0
x - 3 + 3 = 3
x = 3

The zeros and answers:


x = 3