Give a correct interpretation of a 99% confidence level of 0.102 < p < 0.236.

Step-by-step explanation:

Given that there is a confidence interval with lower limit =0.102 and upper limit = 0.236 for p.

Here p is the sample proportion.  

Mean of p = average of lower and upper bound =

Average proportion expected is 0.169

And it can have margin of error as + or - 0.067

THus interpretation is the sample proportion will have a point estimate of 0.169 and we are 99% confident, when sample sizes increase and samples are randomly drawn, the proportion of the samples would fall within the values (0.102, 0.236)

take the logarithm of both sides (the base of the log doesn't matter):

apply the exponent property - this says that :

distribute the log terms on both sides:

group like terms together:

divide through both sides by the coefficient on :

you can do some additional rewriting here using the properties of the logarithm to simplify things if you like: