Mrs. jones buys two toys for her son. the probability that the first toy is defective is 1/3, and the probability that the second toy is defective given that the first toy is defective is 1/5. what is the probability that both toys are defective?

Step-by-step explanation:

Let F denote the event of first  toy is defective and S denote the second toy is defective .

Given: The probability that the first toy is defective

The probability that the second toy is defective given that the first toy is defective  

The formula to calculate the conditional probability is given by :-

Hence, the probability that both toys are defective=

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step-by-step explanation:

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y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )