An expression is shown below f(x)=2x^2-3x-5 part a: what are the x intercepts of the graph of f(x)? show your work. part b: is the vertex of the graph f(x) going to be a minimum or maximum? what are the coordinates of the vertex? justify your answers and show your work. part c: what are the steps you would use to graph f(x)? justify that you can use the answers obtained in part a and b to draw the graph

Given the expression for f(x)=2x^2-3x-5
a] The x-intercepts will be:
At x-intercept, f(x)=0, thus setting f(x)=0 we have:
2x^2-3x-5=0
solving the expression we get:
2x^2+2x-5x-5=0
2x(x+1)-5(x+1)=0
(2x-5)(x+1)=0
thus the x-intercept will be at ()
x=2/5 and x=-1

b] The vertex of the graph will be evaluated as follows:
the vertex form of the equation is given by:
f(x)=(x-k)^2+h
where:
(k,h) is the vertex
thus from the expression f(x)=2x^2-3x-5, the minimum or the maximum point will be at:
x=-b/2a
x=(-(-3)/(2*2))
x=3/4
the value of y will therefore be:
y=f(x)=2(3/4)^2-3(3/4)-5=-49/8
thus the vertex is at:

c] Now that we have the x-intercepts, we know where the graph will cross the x-axis, and the vertex gives us the minimum point and hence we can use them to sketch the graph. The graph will be as shown in the attachment. 

Where are the following equations?