Two points move along a circle of length 120m with a constant speed. if they move in different directions, then they meet every 15 seconds. when going in the same direction, one point catches up to the second every 60 seconds. find the speeds of the points.

Let x and y be the speeds of the two points. The circle is of length 120m that is Circumference of circle is 120m.When the points are moving in opposite directions, they meet in every 15 seconds.That is the points cover 120m in 15 seconds.As they are moving in opposite directions, so the relative speed will be equal to the sum of speeds of both points.Speed= Distance ÷Time = 120÷15=8m per seconds.

x+y=8

When going in the same direction, one point catches up to the second every 60 seconds.Speed= 120÷60=2 m per seconds

x-y=2.

Solving the two equations by elimination method:

x+y=8.

x-y=2

Adding the equations:

2x=10 ,x=5m / sec.

x+y=8

5+y=8

y=3m/sec.

Thus, the speed of the two points is 5 m/s and 3 m/s.

a.

step-by-step explanation:

step 1 distribute 2 to every term in the parentheses

step 2 add 10 on both sides of the equal sign

step-by-step explanation:

given expression is .

now we need to simplify the given expression .

we know that square root is equivalent to the power 1/2. so that means we can take half of the exponents to get the square root of given expression.

expanding that will give a very very large number so let's keep answer in exponent form.