Aball is launched into the sky at 272 feet per second from the roof of a skyscraper 1,344 feet tall. the equation for the ball’s height h at time t seconds is h = -16t2 + 272t + 1344. when will the ball strike the ground?

Time taken to reach the ball to the ground is 21 seconds.                  

Step-by-step explanation:

Given : A ball is launched into the sky at 272 feet per second from the roof of a skyscraper 1,344 feet tall. The equation for the ball’s height h at time t seconds is .

To find : When will the ball strike the ground?

Solution :

The equation for the ball's height 'h' at time 't' is given by,

When the ball strike the ground the height of the ball became zero.

Substitute h=0 in the given equation,

Taking 16 common,

or

Solve by middle term split,

Reject t=-4 as time can never be negative.

Therefore, Time taken to reach the ball to the ground is 21 seconds.

it would more likely be bald eagle because its has more in the box so about 75%.

step-by-step explanation:

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

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